0=-4.9x^2+27x+2.4

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Solution for 0=-4.9x^2+27x+2.4 equation:



0=-4.9x^2+27x+2.4
We move all terms to the left:
0-(-4.9x^2+27x+2.4)=0
We add all the numbers together, and all the variables
-(-4.9x^2+27x+2.4)=0
We get rid of parentheses
4.9x^2-27x-2.4=0
a = 4.9; b = -27; c = -2.4;
Δ = b2-4ac
Δ = -272-4·4.9·(-2.4)
Δ = 776.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{776.04}}{2*4.9}=\frac{27-\sqrt{776.04}}{9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{776.04}}{2*4.9}=\frac{27+\sqrt{776.04}}{9.8} $

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